|
|
|
|
|
|
|
|
1.000 |
2.000 |
4.000 |
8.000 |
|
|
0.500 |
1.000 |
2.000 |
4.000 |
|
|
0.250 |
0.500 |
1.000 |
2.000 |
|
|
0.125 |
0.250 |
0.500 |
1.000 |
For the following ficticious data about a sample of lightbulbs: N = 16, SX = 15,600, SX2 = 15,247,500, calculate the mean, standard deviation (s hat), and the standard error of the mean.
Calculate the mean by dividing SX = 15,600 by N = 16. That gives a mean of 975 hours.
Use the formula below to calculate the standard deviation (s hat)
s hat = square root of:15,247,500 - (15,600)2 / 16 / 15
s hat = square root of: 15,247,500 - 15,210,000 / 15
s hat = square root of: 37,500 / 15
s hat = square root of: 2500
s hat = 50
Now use formula below to get the standard error of the mean:
LL = 975 - 2.131 (12.5) = 948.36 hours
UL = 975 + 2.131 (12.5) = 1001.64
For the 99% confidence interval, find 99% confidence interval from Table D for 15df (N-1). That value is 2.947
LL = 975 - 2.947 (12.5) = 938.16 hours
UL = 975 + 2.947 (12.5) = 1011.84 hours
1000 hours is inside both confidence intervals (barely)
Fourteen social workers took an eight week course in assertiveness. The national mean for assertiveness on the Door Manifest Assertiveness Test is 24.0. Using the following data, construct the 95% confidence interval for the sample mean. Data:
SX = 378, SX2 = 10,400
Solution:
Mean = 378/14 = 27
sx = s(hat)/ ÷N = 1.032
LL = mean - t (sx) = 24.77
UL = mean + t (sx) = 29.23